Integrand size = 16, antiderivative size = 90 \[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\frac {\left (2+\sqrt {6} x^2\right ) \sqrt {\frac {2+x^2+3 x^4}{\left (2+\sqrt {6} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{\frac {3}{2}} x\right ),\frac {1}{24} \left (12-\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {-2-x^2-3 x^4}} \]
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Time = 0.01 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {1117} \[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\frac {\left (\sqrt {6} x^2+2\right ) \sqrt {\frac {3 x^4+x^2+2}{\left (\sqrt {6} x^2+2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{\frac {3}{2}} x\right ),\frac {1}{24} \left (12-\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {-3 x^4-x^2-2}} \]
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Rule 1117
Rubi steps \begin{align*} \text {integral}& = \frac {\left (2+\sqrt {6} x^2\right ) \sqrt {\frac {2+x^2+3 x^4}{\left (2+\sqrt {6} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\sqrt [4]{\frac {3}{2}} x\right )|\frac {1}{24} \left (12-\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {-2-x^2-3 x^4}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.06 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.60 \[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=-\frac {i \sqrt {1-\frac {6 x^2}{-1-i \sqrt {23}}} \sqrt {1-\frac {6 x^2}{-1+i \sqrt {23}}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {6}{-1-i \sqrt {23}}} x\right ),\frac {-1-i \sqrt {23}}{-1+i \sqrt {23}}\right )}{\sqrt {6} \sqrt {-\frac {1}{-1-i \sqrt {23}}} \sqrt {-2-x^2-3 x^4}} \]
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Result contains complex when optimal does not.
Time = 0.60 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.97
method | result | size |
default | \(\frac {2 \sqrt {1-\left (-\frac {1}{4}-\frac {i \sqrt {23}}{4}\right ) x^{2}}\, \sqrt {1-\left (-\frac {1}{4}+\frac {i \sqrt {23}}{4}\right ) x^{2}}\, F\left (\frac {\sqrt {-1-i \sqrt {23}}\, x}{2}, \frac {\sqrt {-33-3 i \sqrt {23}}}{6}\right )}{\sqrt {-1-i \sqrt {23}}\, \sqrt {-3 x^{4}-x^{2}-2}}\) | \(87\) |
elliptic | \(\frac {2 \sqrt {1-\left (-\frac {1}{4}-\frac {i \sqrt {23}}{4}\right ) x^{2}}\, \sqrt {1-\left (-\frac {1}{4}+\frac {i \sqrt {23}}{4}\right ) x^{2}}\, F\left (\frac {\sqrt {-1-i \sqrt {23}}\, x}{2}, \frac {\sqrt {-33-3 i \sqrt {23}}}{6}\right )}{\sqrt {-1-i \sqrt {23}}\, \sqrt {-3 x^{4}-x^{2}-2}}\) | \(87\) |
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none
Time = 0.08 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.40 \[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\frac {1}{24} \, \sqrt {-2} {\left (\sqrt {-23} + 1\right )} \sqrt {\sqrt {-23} - 1} F(\arcsin \left (\frac {1}{2} \, x \sqrt {\sqrt {-23} - 1}\right )\,|\,\frac {1}{12} \, \sqrt {-23} - \frac {11}{12}) \]
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\[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\int \frac {1}{\sqrt {- 3 x^{4} - x^{2} - 2}}\, dx \]
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\[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\int { \frac {1}{\sqrt {-3 \, x^{4} - x^{2} - 2}} \,d x } \]
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\[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\int { \frac {1}{\sqrt {-3 \, x^{4} - x^{2} - 2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {-2-x^2-3 x^4}} \, dx=\int \frac {1}{\sqrt {-3\,x^4-x^2-2}} \,d x \]
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